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4X^2+2X-702=0
a = 4; b = 2; c = -702;
Δ = b2-4ac
Δ = 22-4·4·(-702)
Δ = 11236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11236}=106$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-106}{2*4}=\frac{-108}{8} =-13+1/2 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+106}{2*4}=\frac{104}{8} =13 $
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